Вроде обычный код при процедуре Log in: PHP: <?php require_once 'main_mywebsite.php'; echo "<div class='main'> <h3>Please enter your details to log in</h3>"; $error=$user=$pass=""; if(isset($_POST['user'])) { $user = sanitizeString($_POST['user']); $pass = sanitizeString($_POST['pass']); if($user == ""||$pass == "") { $error = "Not every field is entered"; } else { $result = queryMySQL("SELECT user,pass FROM members WHERE user='$user' AND pass='$pass'); if($result->num_rows == 0) { $error = "<span class ='error'>Username/Password invalid</span><br><br>"; } else { $_SESSION['user']=$user; $_SESSION['pass']=$pass; die("You are now logged in.". Please, <a href = 'members.php&view=$user'>". "click here</a> to continue.<br><br>"); } } } echo<<<_END <form method='post' action='login.php'>$error <span class='fieldname'>Username</span><input type='text' maxlength='16' name='user' value='$user' /><br> <span class='fieldname'>Pasword</span><input type='password' maxlength='16' name='pass' value='$pass'> _END; ?> и почему то выдает ошибку
PHP: $result = queryMySQL("SELECT user,pass FROM members WHERE user='$user' AND pass='$pass'"); Забыл кавычку закрыть!