syntax error, unexpected ':' in ....on line 3 Код (Text): <?php $Id: layoutfunctions.php$ function blockOpen($title) { global $cfg_nuke_it; if(!$cfg_nuke_it) { myEcho('<table border = "1" bordercolor="#000000" cellspacing="1" width="95%">'); myEcho('<tr><td valign = "TOP" witdh="100%" bgcolor="#0099CC">'); myEcho('<b><center>' . $title . '</center></b>'); myEcho('</td></tr><tr><td valign = "TOP" witdh="100%">'); } } function blockClose() { global $cfg_nuke_it; if(!$cfg_nuke_it) { myEcho('</td></tr></table><br>'); } } /**************************************************************************** This part shows the CVS log information (do not edit !) $Log: layoutfunctions.php,v $ Revision 1.1 2003/06/07 18:03:26 ganondorf initial commit ****************************************************************************/ ?>
Разобрался) Теперь нарисовалось Parse error: syntax error, unexpected T_STRING, expecting T_VARIABLE or '$' в line 3 ((