Проблема с выводом из БД

PHP:

1. <?php
2. include ('config.php');
3. $search = $_POST['search'] ;
4. $sql = "SELECT `product` FROM `nestle`,`gerber`,`hipp` WHERE `product`=$search";
5. $result = mysql_query($sql);
6. $myrow_news = mysql_fetch_array($result);
7. echo "<div class=\"newsfeed\">
8.             <div class=\"newstext\">" . $myrow_news['product'] . "</div>
9.     </div>";
10.  
11. ?>

Выдает вот такую ошибку Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in Z:\home\test1.ru\www\components\searchview.php on line 6[/code]